Thanks for posting this update @Derek-Groves , our Chance is 16 and he has had seizures most of his life. It just started out of nowhere when he was a few years old and for a number of years, we tried all kinds of natural and non-natural medications. We tried Chinese herbs, CBD, diet changes then the typical meds like phenobarbitol, all somewhat helped, but he would still have recurring seizures several times a month, or sometimes a week. All in all, he probably had 100 seizures in his lifetime, but luckily no major damage other than he is a bit wobbly and has head tremors once in a while. It does not seem to bother him though and he is otherwise healthy and active for a 16 yr old. Once I found Keppra through trial and error we stuck with it and that seemed to have been the best way to curb the seizures. We went from monthly to maybe once in a few years, during major events like a house move. Today he is on 250mg of Keppra + Zonisomide every 12 hours and that does the trick, if he does have a sezure (we also have concentrated CBD tincture, which we keep bedside, injecting it into his mouth gets him out of it pretty quickly and speeds up recover. We ended up sticking a particular manufacturer for Keppra (Lupin labs), just to make sure no formula variation is introduced.
Coat Color Inheritance in basenji
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It could produce black puppies, red puppies or tri puppies.
I will write more when I get home from work tonight.
ok thank you lvoss. I know you will be writing more when you get home but i just want to ask. How does the B and R show up on a dog. Meaning what does the puppy look like when it has a gene of BbRr? (im not sure if that gene combo is right. just wondering that if it has both dom Blck and dom Red, what would the puppy be in color and what genes would it have?)
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I think R is here only to make difference between "r" (tricolor) and "R" (red). Just way of writing.
This link could help you
http://www.vetgen.com/canine-coat-color.htmlFor basenjis is enough to know about K locus and A locus. Black and brindle are on K locus, red and tricolor are on A locus.
Black is "the most dominant", than brindle/trindle, red and at the end "the least dominant" is tricolor.
If your "R" is for red and "r" for tricolor, your BbRr should be the same as Kk ayat (I suppose
). This is tri-factored black dog who can produce black, red and tricolor pups.Yes i found a punnett square and it had Rr which is why i used it instead of Kk and Yy.
Thanks for the clearing. anyways ok so Kkayat is KkYy (correct?) so the dog is a black dog that has the reces tri and since it has the dom Red gene and a rec tri that is how you got the Black reds and tris? ok i think i get that now. thank you! -
ok i have a question. When you are doing a punnett square, lets say you have a dog that is DDKkYy and DDkkYy. Would you put one parent on top and one on the side and do the addition?
…...kk.....Yy
Kk..Kkkk…KkYy
Yy..kkYy...YYyyHow do you figure out what the puppy is? I dont understand how to take a parents code and put it into the punnett square. I know how to use the punnett square once its ready to be solved but i dont know how to determine where things go and how to evaluate the results (if there are more than 1 letter on each side)
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Dd kk ayay , Dd kk ayat, Dd kk ayaw, Dd kk ayas, Dd kk aya
DD Kk ayay = black
Dd Kk ayay = black
dd Kk ayay = Blue (dog German)
dd Kbrk ayay = blue brindle
DD Kbrk ayay = brindle
Dd Kbrk ayay = brindleDdKbrK ayat
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example
red x whait Dd kk ayay
black x white
Dd KbrK ayayDD Kk ayay = black x white
Dd Kk ayay = black x white
dd Kk ayay = blue (german dog)
DD Kbrk ayay = brindle
Dd Kbrk ayay = brindle
dd Kbrk ayay = fawn brindletwo
red x white Dd kk ayat
black x white Dd KbrK ayatpossible combination
DD Kk ayat = black
Dd Kk ayat = black
dd Kk ayat = blue (german dog)
DD Kk atat =black (mask tricolor)
Dd Kk atat = black (mask tricolor)
dd Kk atat = blue tricolor
DD Kbrk ayay = brindle
Dd Kbrk ayat = brindle
DD Kbrk atat = trindle
Dd Kbrk ayat = brindle
dd Kbrk ayay = blue brindle
dd Kbrk ayat = blue brindle
dd Kbrk atat = blue trindle -
example
red x whait Dd kk ayay
black x white
Dd Kbrk ayayDD kk ayay = red x white
Dd kk ayay = red x white
dd kk ayay = blue fawn
DD Kbrk ayay = brindle
Dd Kbrk ayay = brindle
dd Kbrk ayay = fawn brindletwo
red x white Dd kk ayat
black x white Dd KbrK ayatpossible combination
DD Kk ayat = black
Dd Kk ayat = black
dd Kk ayat = blue (german dog)
DD Kk atat =black (mask tricolor)
Dd Kk atat = black (mask tricolor)
dd Kk atat = blue tricolor
DD Kbrk ayay = brindle
Dd Kbrk ayat = brindle
DD Kbrk atat = trindle
Dd Kbrk ayat = brindle
dd Kbrk ayay = blue brindle
dd Kbrk ayat = blue brindle
dd Kbrk atat = blue trindleIm not sure what all this means. ayat are Yy. umm could you do it with Yy instead of ayay or atat? its just easier for me if you do. thanks
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Big Y is a red
small y - tricolor,saddle,agouti and recesiv gen.Can not have four different meanings -
Misspodhradsky:
tri factored black dog - Kk ayat
tri factored red dog - kk ayatUse punnett square for K locus and another punnett square for A locus:
….......K........k
k….....Kk.......kk
k........Kk.......kkSo, we have Kk (twice) and kk (twice)
A locus:
…............ay..........at
ay….......ayay.....ayat
at..........ayat......atatWe got ayay, ayat (twice), atat
Than put both, K and A locus, together (every K result with every A result):
Kk ayay - black
Kk ayat - tri factored black
Kk atat - tri factored blackkk ayay - red
kk ayat - tri factored red
kk atat - tricolorOr, with your letters:
tri factored black dog - Kk Yy
tri factored red dog - kk Yy….......K........k
k….....Kk.......kk
k........Kk.......kk…............Y..........y
Y….......YY.........Yy
y..........Yy......yyAnd than again, put all together:
Kk YY - black
Kk Yy - tri factored black
Kk yy - tri factored blackkk YY - red
kk Yy - tri factored red
kk yy - tricolor -
Big Y is a red
small y - tricolor,saddle,agouti and recesiv gen.Can not have four different meaningsYes i know that. But when you put ay, at, etc. it confuses me. I need the coding to be is Y,y, K, and k. I think thats it. but i cant follow when people add in different letter cuz i dont understand it
Which sucks cuz when you use letters i know it starts getting easier and easier lol
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Misspodhradsky:
tri factored black dog - Kk ayat
tri factored red dog - kk ayatUse punnett square for K locus and another punnett square for A locus:
….......K........k
k….....Kk.......kk
k........Kk.......kkSo, we have Kk (twice) and kk (twice)
A locus:
…............ay..........at
ay….......ayay.....ayat
at..........ayat......atatWe got ayay, ayat (twice), atat
Than put both, K and A locus, together (every K result with every A result):
Kk ayay - black
Kk ayat - tri factored black
Kk atat - tri factored blackkk ayay - red
kk ayat - tri factored red
kk atat - tricolorOr, with your letters:
tri factored black dog - Kk Yy
tri factored red dog - kk Yy….......K........k
k….....Kk.......kk
k........Kk.......kk…............Y..........y
Y….......YY.........Yy
y..........Yy......yyAnd than again, put all together:
Kk YY - black
Kk Yy - tri factored black
Kk yy - tri factored blackkk YY - red
kk Yy - tri factored red
kk yy - tricolorOH! ok! so you dont do them all together. you do letter with letter and then add them! Oh ok!!! Thank you soo much! That helps alot!
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letter "a" located in the locus A
letter y,t,w,a, talking about hair color
otherwise you can not save -
Letter D intense color
letter d lightened the color -
Kk YY - black
Kk Yy - tri factored black
Kk yy - tri factored blackkk YY - red
kk Yy - tri factored red
kk yy - tricolorWhere did you get the bold ones. I understand how to get the others but if you do it and add them together it makes no sense. …to me
OR do you have to do
1....2
3....41...2
3...4do you have to do 1 with 1, 1 with 2, 1 with 3, 1 with 4....then 2 with 2, 2 with 3, 3 with 4....then 3 with 3, 3 with 4....then 4 with 4. and then take all the alike genes and group them. then take all the unalike genes and
that is how you go the 2 extra genes?
(I used 1,2,3,4 just to make it easier to understand than using letters K, Y, etc.) -
Tiva helping me, thank you
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I am beginning to be wrong.I'm going to sleep until tomorrow. (11 _55 PM)
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from K locus we got:
Kk (and again Kk) - 1
kk (and again kk) - 2from A locus we got:
YY - a
Yy (and again Yy) - b
yy - c1 + a = 1a (Kk YY)
1 + b = 1b (Kk Yy)
1 + c = 1c (Kk yy)
2 + a = 2a (kk YY)
2 + b = 2b (kk Yy)
2 + c = 2c (kk yy) -
from K locus we got:
Kk (and again Kk) - 1
kk (and again kk) - 2from A locus we got:
YY - a
Yy (and again Yy) - b
yy - c1 + a = 1a (Kk YY)
1 + b = 1b (Kk Yy)
1 + c = 1c (Kk yy)
2 + a = 2a (kk YY)
2 + b = 2b (kk Yy)
2 + c = 2c (kk yy)Oh ook i think i get it now, thx for the help in clearifying it. so would "A" always be YY, "b" always be Yy and "C" always be yy? or is that just for this example?
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Just for that example.
