Coat Color Inheritance in basenji

[misspodhradsky]

ok i have a question. When you are doing a punnett square, lets say you have a dog that is DDKkYy and DDkkYy. Would you put one parent on top and one on the side and do the addition?

…...kk.....Yy
Kk..Kkkk…KkYy
Yy..kkYy...YYyy

How do you figure out what the puppy is? I dont understand how to take a parents code and put it into the punnett square. I know how to use the punnett square once its ready to be solved but i dont know how to determine where things go and how to evaluate the results (if there are more than 1 letter on each side)

[Monika]

Dd kk ayay , Dd kk ayat, Dd kk ayaw, Dd kk ayas, Dd kk aya
DD Kk ayay = black
Dd Kk ayay = black
dd Kk ayay = Blue (dog German)
dd Kbrk ayay = blue brindle
DD Kbrk ayay = brindle
Dd Kbrk ayay = brindle

DdKbrK ayat

[Monika]

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

[Monika]

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

[Monika]

example

red x whait Dd kk ayay

black x white
Dd KbrK ayay

DD Kk ayay = black x white
Dd Kk ayay = black x white
dd Kk ayay = blue (german dog)
DD Kbrk ayay = brindle
Dd Kbrk ayay = brindle
dd Kbrk ayay = fawn brindle

two
red x white Dd kk ayat
black x white Dd KbrK ayat

possible combination
DD Kk ayat = black
Dd Kk ayat = black
dd Kk ayat = blue (german dog)
DD Kk atat =black (mask tricolor)
Dd Kk atat = black (mask tricolor)
dd Kk atat = blue tricolor
DD Kbrk ayay = brindle
Dd Kbrk ayat = brindle
DD Kbrk atat = trindle
Dd Kbrk ayat = brindle
dd Kbrk ayay = blue brindle
dd Kbrk ayat = blue brindle
dd Kbrk atat = blue trindle

[misspodhradsky]

@Monika:

example

red x whait Dd kk ayay

black x white
Dd Kbrk ayay

DD kk ayay = red x white
Dd kk ayay = red x white
dd kk ayay = blue fawn
DD Kbrk ayay = brindle
Dd Kbrk ayay = brindle
dd Kbrk ayay = fawn brindle

two
red x white Dd kk ayat
black x white Dd KbrK ayat

possible combination
DD Kk ayat = black
Dd Kk ayat = black
dd Kk ayat = blue (german dog)
DD Kk atat =black (mask tricolor)
Dd Kk atat = black (mask tricolor)
dd Kk atat = blue tricolor
DD Kbrk ayay = brindle
Dd Kbrk ayat = brindle
DD Kbrk atat = trindle
Dd Kbrk ayat = brindle
dd Kbrk ayay = blue brindle
dd Kbrk ayat = blue brindle
dd Kbrk atat = blue trindle

Im not sure what all this means. ayat are Yy. umm could you do it with Yy instead of ayay or atat? its just easier for me if you do. thanks

[Monika]

Big Y is a red
small y - tricolor,saddle,agouti and recesiv gen.Can not have four different meanings

[Tiva]

Misspodhradsky:

tri factored black dog - Kk ayat
tri factored red dog - kk ayat

Use punnett square for K locus and another punnett square for A locus:

….......K........k
k….....Kk.......kk
k........Kk.......kk

So, we have Kk (twice) and kk (twice)

A locus:

…............ay..........at
ay….......ayay.....ayat
at..........ayat......atat

We got ayay, ayat (twice), atat

Than put both, K and A locus, together (every K result with every A result):

Kk ayay - black
Kk ayat - tri factored black
Kk atat - tri factored black

kk ayay - red
kk ayat - tri factored red
kk atat - tricolor

Or, with your letters:
tri factored black dog - Kk Yy
tri factored red dog - kk Yy

….......K........k
k….....Kk.......kk
k........Kk.......kk

…............Y..........y
Y….......YY.........Yy
y..........Yy......yy

And than again, put all together:

Kk YY - black
Kk Yy - tri factored black
Kk yy - tri factored black

kk YY - red
kk Yy - tri factored red
kk yy - tricolor

[misspodhradsky]

@Monika:

Big Y is a red
small y - tricolor,saddle,agouti and recesiv gen.Can not have four different meanings

Yes i know that. But when you put ay, at, etc. it confuses me. I need the coding to be is Y,y, K, and k. I think thats it. but i cant follow when people add in different letter cuz i dont understand it

Which sucks cuz when you use letters i know it starts getting easier and easier lol

[misspodhradsky]

@Tiva:

Misspodhradsky:

tri factored black dog - Kk ayat
tri factored red dog - kk ayat

Use punnett square for K locus and another punnett square for A locus:

….......K........k
k….....Kk.......kk
k........Kk.......kk

So, we have Kk (twice) and kk (twice)

A locus:

…............ay..........at
ay….......ayay.....ayat
at..........ayat......atat

We got ayay, ayat (twice), atat

Than put both, K and A locus, together (every K result with every A result):

Kk ayay - black
Kk ayat - tri factored black
Kk atat - tri factored black

kk ayay - red
kk ayat - tri factored red
kk atat - tricolor

Or, with your letters:
tri factored black dog - Kk Yy
tri factored red dog - kk Yy

….......K........k
k….....Kk.......kk
k........Kk.......kk

…............Y..........y
Y….......YY.........Yy
y..........Yy......yy

And than again, put all together:

Kk YY - black
Kk Yy - tri factored black
Kk yy - tri factored black

kk YY - red
kk Yy - tri factored red
kk yy - tricolor

OH! ok! so you dont do them all together. you do letter with letter and then add them! Oh ok!!! Thank you soo much! That helps alot!

[Monika]

letter "a" located in the locus A

letter y,t,w,a, talking about hair color
otherwise you can not save

[Monika]

Letter D intense color
letter d lightened the color

[misspodhradsky]

@Tiva:

Kk YY - black
Kk Yy - tri factored black
Kk yy - tri factored black

kk YY - red
kk Yy - tri factored red
kk yy - tricolor

Where did you get the bold ones. I understand how to get the others but if you do it and add them together it makes no sense. …to me

OR do you have to do

1....2
3....4

1...2
3...4

do you have to do 1 with 1, 1 with 2, 1 with 3, 1 with 4....then 2 with 2, 2 with 3, 3 with 4....then 3 with 3, 3 with 4....then 4 with 4. and then take all the alike genes and group them. then take all the unalike genes and
that is how you go the 2 extra genes?
(I used 1,2,3,4 just to make it easier to understand than using letters K, Y, etc.)

[Monika]

Tiva helping me, thank you

[Monika]

I am beginning to be wrong.I'm going to sleep until tomorrow. (11 _55 PM)

[Tiva]

from K locus we got:
Kk (and again Kk) - 1
kk (and again kk) - 2

from A locus we got:
YY - a
Yy (and again Yy) - b
yy - c

1 + a = 1a (Kk YY)
1 + b = 1b (Kk Yy)
1 + c = 1c (Kk yy)
2 + a = 2a (kk YY)
2 + b = 2b (kk Yy)
2 + c = 2c (kk yy)

[misspodhradsky]

@Tiva:

from K locus we got:
Kk (and again Kk) - 1
kk (and again kk) - 2

from A locus we got:
YY - a
Yy (and again Yy) - b
yy - c

1 + a = 1a (Kk YY)
1 + b = 1b (Kk Yy)
1 + c = 1c (Kk yy)
2 + a = 2a (kk YY)
2 + b = 2b (kk Yy)
2 + c = 2c (kk yy)

Oh ook i think i get it now, thx for the help in clearifying it. so would "A" always be YY, "b" always be Yy and "C" always be yy? or is that just for this example?

[lvoss]

Just for that example.

[misspodhradsky]

oh. so how do you know what to use then.

[lvoss]

It depends on the alleles of the dog. The litter that I co-bred and have been posting puppy pictures of the parents are KkYy and KkYY. If you do the two punnet square way instead of the 16 punnet square way you would get.

At the K locus

….......K........k
K........KK.......Kk
k........Kk.......kk

At the A locus

.............Y.............y
Y..........YY...........Yy
Y..........YY...........Yy

So we get

from K locus we got:
KK - 1
Kk (we get this twice) - 2
kk - 3

from A locus we got:
YY (we get this twice) - a
Yy (we get this twice) - b

1 + a = 1a (KK YY)
1 + b = 1b (KK Yy)
2 + a = 2a (Kk YY)
2 + b = 2b (Kk Yy)
3 + a = 3a (kk YY)
3 + b = 3b (kk Yy)